A 175 -lb eoman stands on a vinyl floor wearing stiletto high - heel shoes. If the heel has the dimensions shown. determine the average nornal stress she exerts on the ploor and compare it with the average noemal stress developed | 1-41 A 175-lb woman stands on a vinyl floor wearing stiletto high-heel shoes. If the heel has the dimensions shown determine the average normal stress she exerts on the floor and compare it with the average normal stress developed when a man having the same weight is wearing flat-heeled shoes. Assume the load is applied slowly so that dynamic effects can be ignored. Also assume the entire weight is supported only by the heel of one shoe. in. Stiletto shoes A - w 2 in2 2 p 1751b . a A 869 psi Ans in2 Flat-heeled shoes A - tt 2 in2 2 P 175 lb . a A psi Ans in2 From Mechanics of Materials Sixth Edition by R. C. Hibbeler ISBN 0-13-191345-X. 2005 R. C. Hibbeler. Published by Pearson Prentice Hall Pearson Education Inc. Upper Saddle River NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced in any form or by any means without permission in writing from the publisher. 1-42 The 50-lb lamp is supported by three steel rods connected by a ring at A. Determine which rod is subjected to the greater average normal stress and compute its value. Take 0 - 30 . The diameter of each rod is given in the figure. X Fx 0 Faccos 30 -Falcos 45 0 T I Fy 0 FACsin 30 F sin 45 - 50 0 Fac lb Fad lb RodAB 50 . Gab --------- 520 psi J 2 Rod AD . . aAn -------- 634 psi f 2 Rod AC . . -------- 746 psi Ans j 2 From Mechanics of Materials Sixth Edition by R. C. Hibbeler ISBN 0-13-191345-X. 2005 R. C. Hibbeler. Published by Pearson Prentice Hall Pearson Education Inc. Upper Saddle River NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced in any form or by any means without permission in writing from the publisher. 1-43 Solve Prob. 1-42 for 6 45 . L Fx 0 Fxc cos 45 - Fap cos 45 0 TXFy 0 Fac sin45 F sin45 -50 0 Fac .
