Tham khảo tài liệu 'new sat math workbook episode 2 part 8', ngoại ngữ, ngữ pháp tiếng anh phục vụ nhu cầu học tập, nghiên cứu và làm việc hiệu quả | Additional Geometry Topics Data Analysis and Probability 305 8. B Substitute the variable expression provided in each answer choice in turn for x in the function and you ll find that only choice B provides an expression that transforms the function into one whose graph matches the one in the figure fix 1 x 1. To confirm that the line in the figure is in fact the graph of y x 1 substitute the two x y pairs plotted along the line for x and y in the equation. The equation holds for both pairs 3 2 1 -2 -3 1. 9. The correct answer is 25. The total number of bowlers in the league is 240 which is the total of the six numbers in the frequency column. The number of bowlers whose averages fall within the interval 161-200 is 60 37 23 . These 60 bowlers account for 240 or 25 of the league s bowlers. 10. C In the scatter plot B and D are further to the left and further up than all of the other three points A C and E which means that City B and City D receive less rainfall but higher temperatures than any of the other three cities. Statement C provides an accurate general statement based on this information. 11. D Of six marbles altogether two are blue. Hence the chances of drawing a blue marble are 2 in 6 or 1 in 3 which can be expressed as the fraction 3. 12. The correct answer is 3 16. Given that the ratio of the large circle s area to the small circle s area is 2 1 the small circle must comprise 50 of the total area of the large circle. The shaded areas comprise 3 the area of the small circle and so the probability of randomly selecting a point in one of these three regions is 3 x 1 3 8 2 16 . Exercise 1 1. B Since the figure shows a 45 -45 -90 triangle in which the length of one leg is known you can easily apply either the sine or cosine function to determine the length of the hypotenuse. Applying the function sin45 V2 -y- set the value of this function equal to x I opposite 7 t hypotenuse J then solve for x V2 x n r- 7 2 - 2x 7V2 x 7- - . 2 7 2 2. C Since the figure shows
