SAT practise test 10000 part 10

Tham khảo tài liệu 'sat practise test 10000 part 10', ngoại ngữ, ngữ pháp tiếng anh phục vụ nhu cầu học tập, nghiên cứu và làm việc hiệu quả | 15. E The smallest percentage difference is going to be the year where the flu column and the cold column are closest. The converse is not true for the greatest percentage difference. Eyeing the chart is the fastest way to determine the answer. The values in the columns for 2000 look and are the closest and so the percentage difference is the least. E is the answer. 16. D Cold cases white bar have to be greater than flu cases shaded bar so there are only two decades that could be the correct answer 1970 and 1990 choices B and D . In 1970 the number of cold cases is about twice as many as the flu 2 000 to 1 000 so the percentage difference would be 100 . This makes 1990 choice D the answer by default but you can see that the percentage difference works out to about 25 since there were roughly 4 000 cold cases and 3 000 flu cases. 17. A You may want to save Roman numeral questions for the second pass A judicious use of POE will help you out on this one though. Looking at I angles 6 and 12 are both formed by the same intersecting line and they are congruent. Since I must be true you can take this information and cross out any answer choices that do not have I in them. Surprisingly this gets rid B C and D . The answer is either A I only or E I and II only . Since these are the only choices you do not even have to worry about III. Check II and if it must be true then the answer is E . If it isn t true the answer must be A . As it turns out 2 and 9 are not congruent so the answer is choice A . 18. A This problem looks rather complicated but the negative in front of the a simplifies it. If a b is positive then a must be negative and raised to an odd power. To get your head around this consider that if a were positive the entire expression could not be positive. So A must be true. 19. D The first thing to recognize here is that the figure is composed of three triangles and since all the line segments are congruent all the triangles are equilateral and congruent to each .

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