Nó dựa trên hiệu ứng phòng, tạo ra một emf tỷ lệ thuận với mật độ thông lượng khi chuyển đổi được thực hiện tại được cung cấp bởi một nguồn bên ngoài. Nó được phổ biến để phát hiện các emf bằng cách sử dụng một mạch điều tín hiệu tích hợp với việc chuyển đổi hội trường hoặc gắn kết rất chặt chẽ với nó. | Chapter 2 Power Circuit Components The system consists of one machine 2 torque sensors and 2 mechanical loads. The torques and moment of inertia for the machine and the loads are as labelled in the diagram. The reference direction of this mechanical system is from left to right. The equation for this system can be written as d m J JL2 d- Tem - TL1 TL2 The equivalent electrical circuit of the equation is shown below The node voltage in the circuit represents the mechanical speed rnm. The current probe on the left represents the reading of the torque sensor No. 1. Similarly the current probe on the right represents the reading of the torque sensor No. 2. Note that the second current probe is from right to left since Sensor 2 is opposite to the reference direction of the mechanical system. The equivalent circuit also illustrates how mechanical power is transferred. The multiplication of the current to the voltage which is the same as the torque times the mechanical speed represents the mechanical power. If the power is positive it is transferred in the direction of the speed m. 2-52 PSIM User Manual Transfer Function Blocks Chapter 3 Control Circuit Components Transfer Function Blocks A transfer function block is expressed in polynomial form as G 5 k Bn 5 . B2 5 B1 s Bo An s . A2 s A1 s Ao Image TFCTN TFCTN1 Attributes Parameters Description Order n Order n of the transfer function Gain Gain k of the transfer function Coeff. Coefficients of the nominator from Bn to Bo Coeff. Coefficients of the denominator from An to Ao InitialValues Initial values of the state variables xn to X1 for TFCTN1 only Let T s G s U s where T s is the output and U s is the input we can convert the s-domain expression into the differential equation form as follows X1 0 0 0 . 0 -A0 An X1 B0- A0 BnAAn d x2 1 0 0 . 0 -A1 An x2 k B1 - A1 Bn An dt x3 0 1 0 . 0 -A2 An x3 An B2- A2 BnAAn xn 0 0 0 . 1 -An _1 An_ xn Bn -1 - An -1 Bn An_ The output equation in the time domain can
