Proakis J. (2002) Communication Systems Engineering - Solutions Manual (299s) Episode 11

Tham khảo tài liệu 'proakis j. (2002) communication systems engineering - solutions manual (299s) episode 11', kỹ thuật - công nghệ, cơ khí - chế tạo máy phục vụ nhu cầu học tập, nghiên cứu và làm việc hiệu quả | whereas the average transmitted power of the QAM constellation PQAM 8 4A2 4 A PQAM 2 1 73 2 A The relative power advantage of the PSK constellation over the QAM constellation is 8 gain pPSK . . Zj . 7- ------------T - dB PQAM 2 1 V3 2 2 -72 Problem 1 The number of bits per symbol is 4800 4800 k R 24iS 2 Thus a 4-QAM constellation is used for transmission. The probability of error for an M-ary QAM system with M 2k is 3k8b M - 1 N0 With PM 10 5 and k 2 we obtain qL M No_ 5 X 10 6 ệb N0 2 If the bit rate of transmission is 9600 bps then 9600 2400 4 In this case a 16-QAM constellation is used and the probability of error is PM 1 1 2 Ọ 4 Q 3 X 4 X Eb 15 X N0 2 Thus Q 3 X Eb 15 X N0 1 X 10 5 E 3 N0 3 If the bit rate of transmission is 19200 bps then 19200 2400 8 In this case a 256-QAM constellation is used and the probability of error is Pm 1 1 2 1 16 Q 3 X 8 X Eb 255 X N0 2 With PM 10 5 we obtain ịb N0 198 4 The following table gives the SNR per bit and the corresponding number of bits per symbol for the constellations used in parts a -c . k 2 4 8 SNR db As it is observed there is an increase in transmitted power of approximately 3 dB per additional bit per symbol. Problem 1 Although it is possible to assign three bits to each point of the 8-PSK signal constellation so that adjacent points differ in only one bit this is not the case for the 8-QAM constellation of Figure . This is because there are fully connected graphs consisted of three points. To see this consider an equilateral triangle with vertices A B and C. If without loss of generality we assign the all zero sequence 0 0 . 0 to point A then point B and C should have the form B 0 . 0 1 0 . 0 C 0 . 0 1 0 . 0 where the position of the 1 in the sequences is not the same otherwise B C. Thus the sequences of B and C differ in two bits. 2 Since each symbol conveys 3 bits of information the resulted symbol rate is Rs 90 X 106 3 30 X 106 symbols sec 3 The .

Không thể tạo bản xem trước, hãy bấm tải xuống
TỪ KHÓA LIÊN QUAN
TÀI LIỆU MỚI ĐĂNG
Đã phát hiện trình chặn quảng cáo AdBlock
Trang web này phụ thuộc vào doanh thu từ số lần hiển thị quảng cáo để tồn tại. Vui lòng tắt trình chặn quảng cáo của bạn hoặc tạm dừng tính năng chặn quảng cáo cho trang web này.