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Lecture Electric circuits analysis - Lecture 15: Problem solving - series parallel circuits
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In this chapter, the following content will be discussed: Identifying series-parallel relationships, analysis of series-parallel resistive circuits, voltage dividers with resistive loads, ladder networks. | Previous Lectures 13 & 14 Problem Solving-Series Parallel Circuits Identifying Series-Parallel Relationships Analysis of Series-Parallel Resistive Circuits Voltage Dividers with Resistive loads Ladder Networks Problem Solving_Series Parallel Circuits Position 1: RT=30.8 kΩ, V1 = 81.0 V, V2 = 54.0 V, V3 = 27.0V Q.21 The voltage divider in the following Figure has a switched load. Determine the voltage at each tap (V1, V2 , and V3 ) for each position of the switch. (Solved on 3 slides) Lecture 15 Position 2 :RT=35.5 kΩ, R34//RL=15.5K Ω , V1=86.2V, V2=52.4 V, V3=26.2V Position 3:RT=38.7 kΩ, V1=89V, V2=58 V, V3=27V Q.22 Design a voltage divider to provide a 6V output with no load and a minimum of 5.5 V across a 1.0 kΩ load. The source voltage is 24 V, and the unloaded current drain is not to exceed 100 mA. RT=240 Ω, R2=60 Ω, R1= 180 Ω, R2 || RL = 56.6 Ω, VOUT = 5.74 V Problems related to Ladder Networks Q.23 For the circuit shown in the following Figure, calculate the following: (a) Total resistance across the source (b) Total current from the source (c) Current through the 910Ω resistor (d) Voltage from A to point B (Solved on 3 slides) RT = 271 Ω, IT=221 mA, I2= 114 mA, I910 = 58.7 mA, I4 = = 55 mA , V437.5 Ω = 24.06 V,VAB = 12 V RT = 271 Ω, IT=221 mA, I2= 114 mA, I910 = 58.7 mA, I4 = = 55 mA , V437.5 Ω = 24.06 V,VAB = 12 V RT = 271 Ω, IT=221 mA, I2= 114 mA, I910 = 58.7 mA, I4 = = 55 mA , V437.5 Ω = 24.06 V,VAB = 12 V Q.24 Determine the total resistance and the voltage at nodes A, B, and C in the ladder network of the following Figure. (Solved on 2 slides) RT = 6.66 kΩ, RC= 1 kΩ, RB= 1.05 kΩ, RA= 1.06 kΩ, VA = 2.86 V, VB = 1.47 V,VC = 35 mV RT = 6.66 kΩ, RC= 1 kΩ, RB= 1.05 kΩ, RA= 1.06 kΩ, VA = 2.86 V, VB = 1.47 V,VC = 35 mV Q.25 Determine the total resistance between terminals A and B of the ladder network in the given Figure. Also calculate the voltage across each resistor and current in each branch with 10 V between A and B. (Solved on 3 slides) RT = 621 Ω, . | Previous Lectures 13 & 14 Problem Solving-Series Parallel Circuits Identifying Series-Parallel Relationships Analysis of Series-Parallel Resistive Circuits Voltage Dividers with Resistive loads Ladder Networks Problem Solving_Series Parallel Circuits Position 1: RT=30.8 kΩ, V1 = 81.0 V, V2 = 54.0 V, V3 = 27.0V Q.21 The voltage divider in the following Figure has a switched load. Determine the voltage at each tap (V1, V2 , and V3 ) for each position of the switch. (Solved on 3 slides) Lecture 15 Position 2 :RT=35.5 kΩ, R34//RL=15.5K Ω , V1=86.2V, V2=52.4 V, V3=26.2V Position 3:RT=38.7 kΩ, V1=89V, V2=58 V, V3=27V Q.22 Design a voltage divider to provide a 6V output with no load and a minimum of 5.5 V across a 1.0 kΩ load. The source voltage is 24 V, and the unloaded current drain is not to exceed 100 mA. RT=240 Ω, R2=60 Ω, R1= 180 Ω, R2 || RL = 56.6 Ω, VOUT = 5.74 V Problems related to Ladder Networks Q.23 For the circuit shown in the following Figure, calculate the following: (a) Total